The masses of neutron, proton and deuteron in | vedclass

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Question

(A) Given masses: $m_n = 1.00893 	ext{ amu}$, $m_p = 1.00813 	ext{ amu}$, $m_d = 2.01473 	ext{ amu}$.Deuteron $({}_1H^2)$ nucleus consists of one p

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$11.65 	imes 10^{-4}$

Vedclass · Answer

(A) Given masses: $m_n = 1.00893 	ext{ amu}$, $m_p = 1.00813 	ext{ amu}$, $m_d = 2.01473 	ext{ amu}$.Deuteron $({}_1H^2)$ nucleus consists of one proton and one neutron.Mass defect $\Delta m = (m_n + m_p) - m_d$.$\Delta m = (1.00893 + 1.00813) - 2.01473 = 2.01706 - 2.01473 = 0.00233 	ext{ amu}$.Packing fraction is defined as the ratio of mass defect to the mass number $(A)$.For deuteron, $A = 2$.Packing fraction $= \frac{\Delta m}{A} = \frac{0.00233}{2} = 0.001165 = 11.65 	imes 10^{-4}$.

The masses of neutron, proton and deuteron in amu are $1.00893$, $1.00813$ and $2.01473$, respectively. The packing fraction of the deuteron in amu is

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