The maximum current that can be measured by a galvanometer of resistance $40 \,\Omega$ is $10 \,mA$. It is converted into a voltmeter that can read up to $50 \,V$. The resistance to be connected in series with the galvanometer is ... (in $\Omega$)

  • A
    $5040$
  • B
    $4960$
  • C
    $2010$
  • D
    $4050$

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