(C) According to Wien's displacement law,$\lambda_{m} T = b$,where $b$ is Wien's constant.Therefore,$\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\la

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(C) According to Wien's displacement law,$\lambda_{m} T = b$,where $b$ is Wien's constant.Therefore,$\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\lambda_{1} = 11 \times 10^{-5} \text{ cm}$ and $\lambda_{2} = 5.5 \times 10^{-5} \text{ cm}$.We are given $T_{1} = n T_{2}$.Substituting these values into the equation: $(11 \times 10^{-5}) \times (n T_{2}) = (5.5 \times 10^{-5}) \times T_{2}$.Dividing both sides by $T_{2}$ and $10^{-5}$,we get $11n = 5.5$.Thus,$n = \frac{5.5}{11} = 0.5$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

The maximum energy in the thermal radiation from a hot source occurs at a wavelength of $11 \times 10^{-5} \text{ cm}$. According to Wien's law,the temperature of the source (on Kelvin scale) will be $n$ times the temperature of another source (on Kelvin scale) for which the wavelength at maximum energy is $5.5 \times 10^{-5} \text{ cm}$. The value of $n$ is

A
$2$
B
$4$
C
$0.5$
D
$1$

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Level 0 of all question bank

The point $(3,2)$ undergoes the following three transformations in the order given:
$(i)$ Reflection about the line $y=x$.
(ii) Translation by the distance $1$ unit in the positive direction of $x$-axis.
(iii) Rotation by an angle $\frac{\pi}{4}$ about the origin in the anti-clockwise direction.
Then,the final position of the point is:

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$A$ magnetized wire of magnetic moment $M$ and length $l$ is bent into the form of a semicircle of radius $r$. Then its new magnetic moment is:

AP EAMCET 2008

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The $\Delta H_f^o$ for $CO_{2(g)}$,$CO_{(g)}$ and $H_2O_{(g)}$ are $-393.5$,$-110.5$ and $-241.8 \ kJ \ mol^{-1}$ respectively. The standard enthalpy change (in $kJ$) for the reaction $CO_{2(g)} + H_{2(g)} \to CO_{(g)} + H_2O_{(g)}$ is

IIT 2000

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$A$ capacitor of capacitance $C_0$ is charged to a potential $V_0$ and is connected with another capacitor of capacitance $C$ as shown. After closing the switch $S$,the common potential across the two capacitors becomes $V$. The capacitance $C$ is given by

WBJEE 2013

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The minimum deviation produced by a hollow prism filled with a certain liquid is found to be $30^o$. The angle of refraction is also found to be $30^o$. The refractive index of the liquid is

AP EAMCET 2024

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$A$ magnetized wire of magnetic moment $M$ and length $l$ is bent into the form of a semicircle of radius $r$. Then its new magnetic moment is:

The $\Delta H_f^o$ for $CO_{2(g)}$,$CO_{(g)}$ and $H_2O_{(g)}$ are $-393.5$,$-110.5$ and $-241.8 \ kJ \ mol^{-1}$ respectively. The standard enthalpy change (in $kJ$) for the reaction $CO_{2(g)} + H_{2(g)} \to CO_{(g)} + H_2O_{(g)}$ is

$A$ capacitor of capacitance $C_0$ is charged to a potential $V_0$ and is connected with another capacitor of capacitance $C$ as shown. After closing the switch $S$,the common potential across the two capacitors becomes $V$. The capacitance $C$ is given by

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