The maximum number of electrons accommodated in $5f$ orbitals are

If the $n^{th}$ specific period of the periodic table contains $\frac{(n+2)^2}{2}$ elements,then the maximum value of the azimuthal quantum number associated with that period is:

Among the following,the incorrect statement is

Given,
$(A)$ $n=5, m_l=-1$
$(B)$ $n=3, l=2, m_l=-1, m_s=+\frac{1}{2}$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ respectively are:

The electronic configuration together with the quantum numbers of the last electron for lithium $(Li)$ is:

The shape of $d_{xy}$ orbital will be