The maximum number of electrons that can have the set of quantum numbers $n=4$,$m_l=0$,and $m_s=\frac{1}{2}$ is

Given,
$(A)$ $n=5, m_l=-1$
$(B)$ $n=3, l=2, m_l=-1, m_s=+\frac{1}{2}$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ respectively are:

In an atom,how many orbital$(s)$ will have the quantum numbers $n = 3, l = 2$ and $m_l = +2$?

The total number of unpaired electrons in $d$-orbitals of atoms of element of atomic number $29$ is

On the basis of which rules does the arrangement of electrons take place in atoms?

$A$ completely filled $d$ orbital $(d^{10})$ configuration is: