The maximum number of unpaired electrons is p | vedclass

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(A) The electronic configurations of the given elements are as follows:$Fe$ $(Z=26)$: $[Ar] 3d^6 4s^2$. It has $4$ unpaired electrons.$Cu$ $(Z=29)$: $

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$Fe$

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(A) The electronic configurations of the given elements are as follows:$Fe$ $(Z=26)$: $[Ar] 3d^6 4s^2$. It has $4$ unpaired electrons.$Cu$ $(Z=29)$: $[Ar] 3d^{10} 4s^1$. It has $1$ unpaired electron.$Co$ $(Z=27)$: $[Ar] 3d^7 4s^2$. It has $3$ unpaired electrons.$Ni$ $(Z=28)$: $[Ar] 3d^8 4s^2$. It has $2$ unpaired electrons.Thus,the maximum number of unpaired electrons is present in $Fe$.

The maximum number of unpaired electrons is present in

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