The mean deviation about the mean for the fol | vedclass

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(B) Step $1$: Calculate the mean $(\bar{x})$: $\bar{x} = \frac{5+6+7+8+6+9+13+12+15}{9} = \frac{81}{9} = 9$ Step $2$: Calculate the mean deviation abo

Vedclass · Accepted Answer

$2.88$

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(B) Step $1$: Calculate the mean $(\bar{x})$: $\bar{x} = \frac{5+6+7+8+6+9+13+12+15}{9} = \frac{81}{9} = 9$ Step $2$: Calculate the mean deviation about the mean using the formula $\frac{\sum |x_i - \bar{x}|}{N}$: $|5-9| + |6-9| + |7-9| + |8-9| + |6-9| + |9-9| + |13-9| + |12-9| + |15-9|$ $= 4 + 3 + 2 + 1 + 3 + 0 + 4 + 3 + 6 = 26$ Step $3$: Divide by the total number of observations $(N=9)$: $	ext{Mean Deviation} = \frac{26}{9} \approx 2.88$

Class interval	$0-4$	$4-8$	$8-12$	$12-16$	$16-20$
Frequency	$4$	$6$	$8$	$5$	$2$

The mean deviation about the mean for the following data: $5, 6, 7, 8, 6, 9, 13, 12, 15$ is

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