The mean deviation from the mean for the obse | vedclass

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(D) The given observations are $1, 3, 5, 7, 11, 13, 17, 19, 23$.First,we calculate the mean $(\bar{x})$:$\bar{x} = \frac{1+3+5+7+11+13+17+19+23}{9} =

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$6 \frac{2}{9}$

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(D) The given observations are $1, 3, 5, 7, 11, 13, 17, 19, 23$.First,we calculate the mean $(\bar{x})$:$\bar{x} = \frac{1+3+5+7+11+13+17+19+23}{9} = \frac{99}{9} = 11$.The mean deviation about the mean is given by $\frac{1}{n} \sum_{i=1}^{n} |x_i - \bar{x}|$.Mean deviation $= \frac{1}{9} [|1-11| + |3-11| + |5-11| + |7-11| + |11-11| + |13-11| + |17-11| + |19-11| + |23-11|]$.Mean deviation $= \frac{1}{9} [10 + 8 + 6 + 4 + 0 + 2 + 6 + 8 + 12]$.Mean deviation $= \frac{56}{9} = 6 \frac{2}{9}$.

$\text{Marks}$	$10$	$15$	$20$	$25$	$30$
$\text{Number of students}$	$2$	$4$	$6$	$8$	$5$

$x_i$	$3$	$6$	$9$	$12$	$13$	$15$	$21$	$22$
$f_i$	$3$	$4$	$5$	$2$	$4$	$5$	$4$	$3$

$x_i$	$2$	$4$	$5$	$7$	$9$
$f_i$	$2$	$4$	$10$	$8$	$6$

The mean deviation from the mean for the observations $1, 3, 5, 7, 11, 13, 17, 19, 23$ is

Similar Questions

The mean deviation from the mean of the data given below is
$\text{Marks}$ $10$ $15$ $20$ $25$ $30$
$\text{Number of students}$ $2$ $4$ $6$ $8$ $5$

The mean deviation from the median for the following data is
$x_i$ $2$ $3$ $5$ $7$ $9$
$f_i$ $8$ $6$ $4$ $2$ $1$

The mean deviation from the median for the following distribution (corrected to $2$ decimals) is
$x_i$ $3$ $6$ $9$ $12$ $13$ $15$ $21$ $22$
$f_i$ $3$ $4$ $5$ $2$ $4$ $5$ $4$ $3$

The mean deviation about the mean of the set of first $n$ natural numbers,when $n$ is an even number,is equal to:

The mean deviation about the mean for the following data is:
$x_i$ $2$ $4$ $5$ $7$ $9$
$f_i$ $2$ $4$ $10$ $8$ $6$

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