The mean deviation from the mean of the discr | vedclass

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(C) The mean of the observations is given by the ratio of the sum of observations to the number of observations.Sum $= 1 + 3 + 4 + 7 + 11 + 18 + 29 +

Vedclass · Accepted Answer

$\frac{176}{9}$

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(C) The mean of the observations is given by the ratio of the sum of observations to the number of observations.Sum $= 1 + 3 + 4 + 7 + 11 + 18 + 29 + 47 + 78 = 198$.Mean $(\bar{x}) = \frac{198}{9} = 22$.Now,the mean deviation from the mean is calculated as $M.D. = \frac{\sum |x_i - \bar{x}|}{n}$.$M.D. = \frac{|1-22| + |3-22| + |4-22| + |7-22| + |11-22| + |18-22| + |29-22| + |47-22| + |78-22|}{9}$.$M.D. = \frac{21 + 19 + 18 + 15 + 11 + 4 + 7 + 25 + 56}{9}$.$M.D. = \frac{176}{9}$.

$x_i$	$5$	$7$	$9$	$10$	$12$	$15$
$f_i$	$8$	$6$	$2$	$2$	$2$	$6$

The mean deviation from the mean of the discrete data $1, 3, 4, 7, 11, 18, 29, 47, 78$ is

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