The mean of 10 observations is calculated as | vedclass

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(A) Given that the number of observations $n = 10$ and the incorrect mean $\bar{x}_{incorrect} = 22.7$.Sum of observations (incorrect) $= n 	imes \ba

Vedclass · Accepted Answer

$26.3$

Vedclass · Answer

(A) Given that the number of observations $n = 10$ and the incorrect mean $\bar{x}_{incorrect} = 22.7$.Sum of observations (incorrect) $= n 	imes \bar{x}_{incorrect} = 10 	imes 22.7 = 227$.The correct sum is obtained by subtracting the incorrect value and adding the correct value: $	ext{Correct Sum} = 227 - 15 + 51$.$	ext{Correct Sum} = 227 + 36 = 263$.The correct mean is $\bar{x}_{correct} = \frac{	ext{Correct Sum}}{n} = \frac{263}{10} = 26.3$.Therefore,the correct mean is $26.3$.

The mean of $10$ observations is calculated as $22.7$. It was later noticed that one observation was taken as $15$ instead of $51$ by mistake. Then,the correct mean of the data is ........

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