The mean of $5$ observations is $4.4$ and their variance is $8.24$. If three observations are $1, 2$ and $6$,the other two observations are

  • A
    $4$ and $8$
  • B
    $4$ and $9$
  • C
    $5$ and $7$
  • D
    $5$ and $9$

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Similar Questions

The mean of five observations is $4$ and their variance is also $4$. If three of the five observations are $1, 3, 4$,then the product of the other two is:

Let $r$ be the range and $S^2 = \frac{1}{n - 1} \sum_{i = 1}^n (x_i - \bar{x})^2$ be the variance of a set of observations $x_1, x_2, \dots, x_n$. Then:

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The sum of two positive integers is $100$. The probability that their product is greater than $1000$ is

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The mean and standard deviation of $100$ observations were calculated as $40$ and $5.1$ respectively. Later on,it was found that one of the observations was taken as $50$ in place of $40$. If the wrong entry is replaced by the correct one,then the sum of the squares of all the observations is:

Consider the given data with frequency distribution:
$x_{i} = \{3, 8, 11, 10, 5, 4\}$
$f_{i} = \{5, 2, 3, 2, 4, 4\}$
Match each entry in List-$I$ to the correct entries in List-$II$.
List-$I$List-$II$
$(P)$ The mean of the above data is$(1) 2.5$
$(Q)$ The median of the above data is$(2) 5$
$(R)$ The mean deviation about the mean of the above data is$(3) 6$
$(S)$ The mean deviation about the median of the above data is$(4) 2.7$
$(5) 2.4$

The correct option is :

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