The mean of discrete observations $y_1, y_2, \ldots, y_n$ is given by:
- A$\frac{\sum_{i=1}^n y_i}{n}$
- B$\frac{\sum_{i=1}^n y_i}{\sum_{i=1}^n i}$
- C$\frac{\sum_{i=1}^n y_i f_i}{n}$
- D$\frac{\sum_{i=1}^n y_i f_i}{\sum_{i=1}^n f_i}$
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Similar Questions
The following data gives the distribution of height of students. The median of the distribution is:
Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$ No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$
| Height (in $cm$) | $160$ | $150$ | $152$ | $161$ | $156$ | $154$ | $155$ |
| No of students | $12$ | $8$ | $4$ | $4$ | $3$ | $3$ | $7$ |
Medium
View SolutionThe mean and the median of the following ten numbers in increasing order $10, 22, 26, 29, 34, x, 42, 67, 70, y$ are $42$ and $35$ respectively. Then,$\frac{y}{x}$ is equal to:
DifficultJEE MAIN 2019
View SolutionThe geometric mean of the numbers $4, 5, 10, 20, 25$ is .........
Easy
View SolutionIf for some positive $x \in R$,the frequency distribution of the marks obtained by $20$ students in a certain test is as follows:
Marks $2$ $3$ $5$ $7$ Frequency $(x+1)^2$ $2x-5$ $x^2-3x$ $x$
Then the mean of the marks is:
| Marks | $2$ | $3$ | $5$ | $7$ |
|---|---|---|---|---|
| Frequency | $(x+1)^2$ | $2x-5$ | $x^2-3x$ | $x$ |
Then the mean of the marks is:
The mean of a set of numbers is $\bar{x}$. If each number is multiplied by $\lambda$,then the mean of the new set is
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