The median class in the following frequency d | vedclass

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(D) First,calculate the cumulative frequency $(cf)$ for each class:$1$. Class $10-25$: $cf = 5$$2$. Class $25-40$: $cf = 5 + 21 = 26$$3$. Class $40-55

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$55-70$

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(D) First,calculate the cumulative frequency $(cf)$ for each class:$1$. Class $10-25$: $cf = 5$$2$. Class $25-40$: $cf = 5 + 21 = 26$$3$. Class $40-55$: $cf = 26 + 21 = 47$$4$. Class $55-70$: $cf = 47 + 8 = 55$$5$. Class $70-85$: $cf = 55 + 25 = 80$$6$. Class $85-100$: $cf = 80 + 20 = 100$The total frequency $n = 100$.Calculate $\frac{n}{2} = \frac{100}{2} = 50$.The median class is the class whose cumulative frequency is just greater than or equal to $\frac{n}{2} = 50$.Looking at the cumulative frequencies: $5, 26, 47, 55, 80, 100$. The first cumulative frequency greater than $50$ is $55$,which corresponds to the class $55-70$.Therefore,the median class is $55-70$.

Weekly income	Number of families
$0-1000$	$250$
$1000-2000$	$190$
$2000-3000$	$100$
$3000-4000$	$40$
$4000-5000$	$15$
$5000-6000$	$5$
Total	$600$

The median class in the following frequency distribution is $\ldots \ldots \ldots \ldots .$

Class $10-25$ $25-40$ $40-55$ $55-70$ $70-85$ $85-100$

Frequency $5$ $21$ $21$ $8$ $25$ $20$

Similar Questions

$\sum_{i=1}^{10} (x_i - \bar{x}) = \dots$

Weekly income of $600$ families is tabulated below:

Weekly income Number of families

$0-1000$ $250$

$1000-2000$ $190$

$2000-3000$ $100$

$3000-4000$ $40$

$4000-5000$ $15$

$5000-6000$ $5$

Total $600$

Compute the median income (in $Rs.$).

For a given frequency distribution,$\Sigma f_{i} d_{i} = -50$,$\Sigma f_{i} = 200$ and $A = 62.5$. Then the mean $\bar{x} = $ ........

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Class	$10-25$	$25-40$	$40-55$	$55-70$	$70-85$	$85-100$
Frequency	$5$	$21$	$21$	$8$	$25$	$20$

The median class in the following frequency distribution is $\ldots \ldots \ldots \ldots .$ Class $10-25$ $25-40$ $40-55$ $55-70$ $70-85$ $85-100$ Frequency $5$ $21$ $21$ $8$ $25$ $20$