The median class of the following frequency d | vedclass

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(A) To find the median class,we first determine the total frequency $n = \sum f_i = 6 + 10 + 5 + 6 + 4 + 2 + 2 = 35$.The median class is the class int

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$30-40$

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(A) To find the median class,we first determine the total frequency $n = \sum f_i = 6 + 10 + 5 + 6 + 4 + 2 + 2 = 35$.The median class is the class interval corresponding to the cumulative frequency just greater than $\frac{n}{2}$.Here,$\frac{n}{2} = \frac{35}{2} = 17.5$.Let's calculate the cumulative frequencies $(cf)$:Class $10-20$: $cf = 6$Class $20-30$: $cf = 6 + 10 = 16$Class $30-40$: $cf = 16 + 5 = 21$Since $21$ is the first cumulative frequency greater than $17.5$,the corresponding class interval $30-40$ is the median class.

Class	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$6$	$10$	$5$	$6$	$4$	$2$	$2$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
Frequency	$7$	$16$	$25$	$32$	$20$

The median class of the following frequency distribution is ...........
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $6$ $10$ $5$ $6$ $4$ $2$ $2$

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The median class of the following frequency distribution is ...........Class$10-20$$20-30$$30-40$$40-50$$50-60$$60-70$$70-80$Frequency$6$$10$$5$$6$$4$$2$$2$