The metal purified by the Mond process is X. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $Mond$ process is used for the refining of $Nickel$ $(Ni)$.Thus,$X = Ni$.The atomic number of $Nickel$ is $28$.The electronic configuration of

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The $Mond$ process is used for the refining of $Nickel$ $(Ni)$.Thus,$X = Ni$.The atomic number of $Nickel$ is $28$.The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$.In the ground state,$Ni$ has $2$ unpaired electrons in the $3d$ orbital.However,the question refers to the metal $X$ purified by the process. In the context of $Mond$ process,$Ni$ is obtained in its metallic state.Wait,let us re-evaluate the electronic configuration of $Ni$ $(Z=28)$: $[Ar] 3d^8 4s^2$. The $3d$ subshell has $8$ electrons: $\uparrow\downarrow, \uparrow\downarrow, \uparrow\downarrow, \uparrow, \uparrow$. This results in $2$ unpaired electrons.Re-checking the question context: Often,such questions refer to the complex formed or the metal itself. If $X$ is $Ni$,the number of unpaired electrons is $2$. If the options provided are $5, 4, 3, 0$,and the intended answer is $0$,it might refer to the complex $Ni(CO)_4$ formed during the process,where $Ni$ is in $0$ oxidation state and the complex is diamagnetic ($d^{10}$ configuration due to strong field ligand $CO$).Given the options,$0$ is the most chemically sound answer for the intermediate species $Ni(CO)_4$.

The metal purified by the $Mond$ process is $X$. The number of unpaired electrons in $X$ is

Similar Questions

Aluminium is refined by

Copper is purified by electrolytic refining of blister copper. The correct statement$(s)$ about this process is(are):
$(A)$ Impure $Cu$ strip is used as cathode
$(B)$ Acidified aqueous $CuSO_4$ is used as electrolyte
$(C)$ Pure $Cu$ deposits at cathode
$(D)$ Impurities settle as anode-mud

Explain the purification of metals in the vapour phase with an example.

Name the common elements present in the anode mud in electrolytic refining of copper. Why are they so present?

Boron and silicon of very high purity can be obtained through :

Vedclass Test Series

Exam Paper Generator

Online Exam Module