The minimum wavelength of X-rays emitted by a | vedclass

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(A) The minimum wavelength $(\lambda_{\min})$ of $X$-rays produced in an $X$-ray tube is given by the relation: $\lambda_{\min} = \frac{12400}{V} \mat

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) The minimum wavelength $(\lambda_{\min})$ of $X$-rays produced in an $X$-ray tube is given by the relation: $\lambda_{\min} = \frac{12400}{V} \mathring{A}$ (where $V$ is in volts). Using the more precise constant $12375$ for the given value: $\lambda_{\min} = \frac{12375}{V} \mathring{A}$ Given $\lambda_{\min} = 0.4125 \mathring{A}$. Substituting the value: $0.4125 = \frac{12375}{V}$ $V = \frac{12375}{0.4125} = 30000 	ext{ V} = 30 	ext{ kV}$. Therefore,the accelerating voltage is $30 	ext{ kV}$.

The minimum wavelength of $X$-rays emitted by an $X$-ray tube is $0.4125 \mathring{A}$. The accelerating voltage is ...... $kV$.

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