The minimum wavelength of the $X$-rays produced by electrons accelerated through a potential difference of $V$ volts is directly proportional to

The graph that correctly represents the relation of frequency $\nu$ of a particular characteristic $X$-ray with the atomic number $Z$ of the material is

According to Moseley's law,the frequency of a spectral line in the $X$-ray spectrum varies as:

The $K_{\alpha}$ $X$-ray emission from tungsten occurs at $\lambda = 0.021 \ nm$. The energy difference between the $K$ and $L$ levels in the atom is:

Electrons with energy $80 \ keV$ are incident on the tungsten target of an $X$-ray tube. $K$-shell electrons of tungsten have an ionization energy of $72.5 \ keV$. The $X$-rays emitted by the tube contain only:

The difference between $\lambda_{K_{\alpha}}$ and $\lambda_{min}$ becomes twice if the accelerating potential changes from $3100 \ V$ to $12400 \ V$. Find $\lambda_{K_{\alpha}}$ in $\mathring{A}$. (Given $hc = 12400 \ eV \mathring{A}$)