The molar specific heat capacity of a diatomi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a diatomic gas,the degrees of freedom $f_1 = 5$.The molar specific heat capacity at constant volume is $C_{v_1} = \frac{f_1 R}{2} = \frac{5 R}

Vedclass · Accepted Answer

$\frac{3 C}{7}$

Vedclass · Answer

(B) For a diatomic gas,the degrees of freedom $f_1 = 5$.The molar specific heat capacity at constant volume is $C_{v_1} = \frac{f_1 R}{2} = \frac{5 R}{2}$.The molar specific heat capacity at constant pressure is $C_{p_1} = C_{v_1} + R = \frac{5 R}{2} + R = \frac{7 R}{2} = C$.For a monoatomic gas,the degrees of freedom $f_2 = 3$.The molar specific heat capacity at constant volume is $C_{v_2} = \frac{f_2 R}{2} = \frac{3 R}{2}$.Now,taking the ratio $\frac{C}{C_{v_2}} = \frac{\frac{7 R}{2}}{\frac{3 R}{2}} = \frac{7}{3}$.Therefore,$C_{v_2} = \frac{3 C}{7}$.

The molar specific heat capacity of a diatomic gas at constant pressure is $C$. The molar specific heat capacity of a monoatomic gas at constant volume is

Similar Questions

The amount of heat energy required to raise the temperature of $1\, g$ of Helium at $NTP$ from $T_1\, K$ to $T_2\, K$ is:

Select the incorrect relation. (Where symbols have their usual meanings)

The specific heat at constant pressure and at constant volume for an ideal gas are $C_p$ and $C_v$,and its adiabatic and isothermal elasticities are $E_{\phi}$ and $E_{\theta}$ respectively. The ratio of $E_{\phi}$ to $E_{\theta}$ is

The specific heat capacity of a monatomic gas at constant volume is $x \%$ of its specific heat capacity at constant pressure. Then $x=$

At constant volume,the specific heat of a gas is $\frac{3R}{2}$. Then the value of $\gamma$ will be ....

Vedclass Test Series

Exam Paper Generator

Online Exam Module