The molecular size of $ICl$ and $Br_2$ is approximately the same,but the $b.p.$ of $ICl$ is about $40 \ ^oC$ higher than that of $Br_2$. This is because:

  • A
    $ICl$ bond is stronger than $Br-Br$ bond
  • B
    $IE$ of iodine $< IE$ of bromine
  • C
    $ICl$ is polar while $Br_2$ is nonpolar
  • D
    $I$ has a larger size than $Br$

Explore More

Similar Questions

The dipole moment of chlorobenzene is $1.5 \ D$. The dipole moment of $o-$dichlorobenzene is (in $D$)

Which of the following compounds has the highest dipole moment?

In terms of polar character,which of the following orders is correct?

Difficult
View Solution

If $Q$ is the magnitude of charge and $r$ is the distance between the centres of positive and negative charges,then the dipole moment $(\mu)$ is given by:

Dipole moment of $HCl = 1.03 \ D$,$HI = 0.38 \ D$. Bond length of $HCl = 1.3 \ \mathring{A}$ and $HI = 1.6 \ \mathring{A}$. The ratio of the fraction of electric charge,$\delta$,existing on each atom in $HCl$ and $HI$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo