The moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is $I$. What is the ratio of the moment of inertia about a parallel axis tangential to its rim to the moment of inertia about a parallel axis passing through a point midway between the centre and the rim (in $:1$)?

Four identical discs each of mass $M$ and diameter $a$ are arranged in a plane as shown in the figure. If the moment of inertia of the system about $OO'$ is $\frac{x}{4} Ma^2$,then the value of $x$ will be:

The moment of inertia of a thin square plate $PQRS$ of uniform thickness,about an axis passing through the centre '$O$' and perpendicular to the plane of the plate is (where $I_1, I_2, I_3, I_4$ are respectively the moments of inertia about axes $1, 2, 3, 4$ which are in the plane of the plate as shown in the figure):

$M$ and $R$ are the mass and radius of a disc. $A$ small disc of radius $R/3$ is removed from the bigger disc as shown in the figure. The moment of inertia of the remaining part of the bigger disc about an axis $\text{AB}$ passing through the centre $O$ and perpendicular to the plane of the disc is $\frac{4}{x} MR^2$. The value of $x$ is . . . . . . .

The moment of inertia of a thin uniform rod of mass $M$ and length $L$,about an axis perpendicular to the length of the rod and at a distance $L/4$ from one end is:

The moment of inertia of a uniform circular disc about a diameter is $I$. What is its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim (in $I$)?