The moment of inertia of a uniform circular d | vedclass

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(A) According to the theorem of parallel axes,the moment of inertia $I$ about an axis parallel to the axis passing through the center of mass is given

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$B$

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(A) According to the theorem of parallel axes,the moment of inertia $I$ about an axis parallel to the axis passing through the center of mass is given by $I = I_{CM} + Ma^2$,where $M$ is the mass of the disc,$I_{CM}$ is the moment of inertia about the center of mass,and $a$ is the perpendicular distance between the two axes.Since the axis is perpendicular to the disc and passes through the given points,the distance $a$ is the distance of the point from the center of the disc $(A)$.For the moment of inertia $I$ to be maximum,the distance $a$ must be maximum.Looking at the figure,point $B$ is on the circumference of the disc,making its distance from the center $A$ the radius of the disc,which is the maximum distance among the given points.Therefore,the moment of inertia is maximum about an axis passing through point $B$.

The moment of inertia of a uniform circular disc is maximum about an axis perpendicular to the disc and passing through which of the following points?

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