The momentum of a photon is 2 times 10^{-16} | vedclass

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(C) The relationship between the energy $E$ and momentum $p$ of a photon is given by $E = p 	imes c$,where $c$ is the speed of light.Given momentum $

Vedclass · Accepted Answer

$6 	imes 10^{-6} 	ext{ erg}$

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(C) The relationship between the energy $E$ and momentum $p$ of a photon is given by $E = p 	imes c$,where $c$ is the speed of light.Given momentum $p = 2 	imes 10^{-16} 	ext{ g} \cdot 	ext{cm/s}$.The speed of light $c = 3 	imes 10^{10} 	ext{ cm/s}$.Substituting these values into the formula:$E = (2 	imes 10^{-16} 	ext{ g} \cdot 	ext{cm/s}) 	imes (3 	imes 10^{10} 	ext{ cm/s})$$E = 6 	imes 10^{-6} 	ext{ g} \cdot 	ext{cm}^2/	ext{s}^2$Since $1 	ext{ erg} = 1 	ext{ g} \cdot 	ext{cm}^2/	ext{s}^2$,the energy is $6 	imes 10^{-6} 	ext{ erg}$.

The momentum of a photon is $2 \times 10^{-16} \text{ g} \cdot \text{cm/s}$. Its energy is:

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