The most basic hydroxide among the following | vedclass

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(B) The basicity of lanthanide hydroxides decreases as the ionic radius decreases with an increase in atomic number (lanthanide contraction).Therefore

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$Ce(OH)_3$

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(B) The basicity of lanthanide hydroxides decreases as the ionic radius decreases with an increase in atomic number (lanthanide contraction).Therefore,the basicity follows the order: $La(OH)_3 > Ce(OH)_3 > ... > Lu(OH)_3$.Comparing $Ce(OH)_3$ and $Ce(OH)_4$,the hydroxide with the lower oxidation state of the metal $(Ce^{3+})$ is more basic than the one with the higher oxidation state $(Ce^{4+})$ because the higher charge density of $Ce^{4+}$ increases the covalent character of the $Ce-OH$ bond.Thus,$Ce(OH)_3$ is the most basic among the given options.

The most basic hydroxide among the following is

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