The most stable carbocation is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of a carbocation is determined by the electron-donating or electron-withdrawing nature of the substituents attached to the benzene r

Vedclass · Accepted Answer

$p-Methoxybenzyl$ carbocation

Vedclass · Answer

(A) The stability of a carbocation is determined by the electron-donating or electron-withdrawing nature of the substituents attached to the benzene ring.$1$. The $-OCH_3$ group in $p-methoxybenzyl$ carbocation exerts a strong $+M$ (mesomeric) effect,which significantly stabilizes the positive charge through resonance.$2$. The $-CH_3$ group in $p-methylbenzyl$ carbocation provides stability through $+I$ (inductive) effect and hyperconjugation.$3$. The $-NO_2$ group in $p-nitrobenzyl$ carbocation is a strong electron-withdrawing group ($-M$ and $-I$ effects),which destabilizes the carbocation.$4$. The unsubstituted $benzyl$ carbocation has only resonance stabilization from the benzene ring.Comparing these,the $+M$ effect of the $-OCH_3$ group provides the greatest stabilization to the carbocation. Therefore,$p-methoxybenzyl$ carbocation is the most stable.

Similar Questions

In which pair is the second ion more stable than the first?

Consider the following statements. Of these statements:
$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$
$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$

Which of the following is not expected to be an intermediate of the following reaction?

Identify the most stable free radical from the following.

Arrange the carbanions,$(CH_3)_3\overline{C}$,$\overline{C}Cl_3$,$(CH_3)_2\overline{C}H$,$C_6H_5\overline{C}H_2$ in order of their decreasing stability:

Vedclass Test Series

Exam Paper Generator

Online Exam Module