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Question

(B) The correct option is $B$. The conversion of $2-$phenylpropanamide into $1-$phenylethylamine involves the loss of a carbonyl carbon atom,which is

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$Br_{2}, NaOH$

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(B) The correct option is $B$. The conversion of $2-$phenylpropanamide into $1-$phenylethylamine involves the loss of a carbonyl carbon atom,which is characteristic of the Hofmann bromamide degradation reaction.The reaction is as follows:$CH_{3}CH(Ph)CONH_{2} + Br_{2} + 4NaOH \rightarrow CH_{3}CH(Ph)NH_{2} + Na_{2}CO_{3} + 2NaBr + 2H_{2}O$In this reaction,the amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide. The alkyl or aryl group migrates from the carbonyl carbon to the nitrogen atom,resulting in the formation of a primary amine with one carbon atom less than the starting amide.

The most suitable reagent for the conversion of $2-$phenylpropanamide into $1-$phenylethylamine is $....$

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