The negation of the contrapositive of the sta | vedclass

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(B) The contrapositive of the statement $p \rightarrow (\sim q \wedge r)$ is $\sim (\sim q \wedge r) \rightarrow \sim p$. By De Morgan's law,this is e

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$(q \vee \sim r) \wedge p$

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(B) The contrapositive of the statement $p \rightarrow (\sim q \wedge r)$ is $\sim (\sim q \wedge r) \rightarrow \sim p$. By De Morgan's law,this is equivalent to $(q \vee \sim r) \rightarrow \sim p$. The negation of the contrapositive is $\sim [(q \vee \sim r) \rightarrow \sim p]$. Using the logical equivalence $\sim (A \rightarrow B) \equiv A \wedge \sim B$,we get $(q \vee \sim r) \wedge \sim (\sim p)$. This simplifies to $(q \vee \sim r) \wedge p$.

The negation of the contrapositive of the statement $p \rightarrow (\sim q \wedge r)$ is

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