The negation of the inverse of the statement | vedclass

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(C) Step $1$: The given statement is $S = \sim p \lor \sim q$.Step $2$: The inverse of a statement $A \lor B$ is $\sim A \lor \sim B$. However, for a

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$\sim p \land \sim q$

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(C) Step $1$: The given statement is $S = \sim p \lor \sim q$.Step $2$: The inverse of a statement $A \lor B$ is $\sim A \lor \sim B$. However, for a conditional statement $p 	o q$, the inverse is $\sim p 	o \sim q$. Assuming the statement is treated as a logical expression, the inverse of $\sim p \lor \sim q$ is $\sim(\sim p) \lor \sim(\sim q)$, which simplifies to $p \lor q$.Step $3$: The negation of the inverse $p \lor q$ is $\sim(p \lor q)$.Step $4$: By De Morgan's Law, $\sim(p \lor q) \equiv \sim p \land \sim q$.

The negation of the inverse of the statement $\sim p \lor \sim q$ is...

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