The net gain of energy from one gram molecule | vedclass

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Question

(C) During aerobic respiration,the complete oxidation of one molecule of glucose $(C_6H_{12}O_6)$ occurs through glycolysis,the link reaction,the Kreb

Vedclass · Accepted Answer

$38$

Vedclass · Answer

(C) During aerobic respiration,the complete oxidation of one molecule of glucose $(C_6H_{12}O_6)$ occurs through glycolysis,the link reaction,the Krebs cycle,and the electron transport system $(ETS)$.In eukaryotic cells,the net gain is typically $36$ $ATP$ molecules because $2$ $ATP$ are consumed to transport $NADH$ produced during glycolysis into the mitochondria via the shuttle system.However,in prokaryotic cells,there is no such transport cost,resulting in a net gain of $38$ $ATP$ molecules.In standard biological contexts,$38$ $ATP$ is often cited as the theoretical maximum yield per glucose molecule.

The net gain of energy from one gram molecule of glucose during aerobic respiration is (in $ATP$)

Similar Questions

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