The net impedance of the circuit (as shown in the figure) will be $...........\,\Omega$.

In the circuit shown in the figure,if both the bulbs $B_1$ and $B_2$ are identical,then:

$A$ series $LCR$ circuit consists of an inductor $L$,a capacitor $C$,and a resistor $R$ connected across a source of emf $\varepsilon = \varepsilon_0 \sin \omega t$. When $\omega L = \frac{1}{\omega C}$,the current in the circuit is $I_0$. If the angular frequency of the source is changed to $\omega^{\prime}$,the current in the circuit becomes $\frac{I_0}{2}$. Then,the value of $\left|\omega^{\prime} L - \frac{1}{\omega^{\prime} C}\right|$ is

For the given figures,choose the correct option:

In a series $R-L-C$ circuit,$R = 300 \, \Omega$,$L = 0.9 \, H$,$C = 2.0 \, \mu F$,and $\omega = 1000 \, rad/s$. The impedance of the circuit is ........ $\Omega$.

An $AC$ source is connected in the given series $LCR$ circuit. The $RMS$ potential difference across the capacitor of $20 \mu F$ is . . . . . . $V$.
$V = 50 \sqrt{2} \sin 100 t$ volt