(B) Neil Bartlett observed that the first ionization enthalpy of $Xe$ is quite close to that of $O_2$. He prepared a red-colored compound by reacting

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) Neil Bartlett observed that the first ionization enthalpy of $Xe$ is quite close to that of $O_2$. He prepared a red-colored compound by reacting $Xe$ with $PtF_6$,which he formulated as $Xe^+[PtF_6]^-$. Thus,$XePtF_6$ was the first noble gas compound prepared by Bartlett.

Class 12 Chemistry p-Block Elements (Class 12)Noble gases

Medium

The noble gas compound prepared by Bartlett was

A
$XeO_3$
B
$XePtF_6$
C
$KrF_2$
D
$XeF_2$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

p-Block Elements (Class 12)

Subtopic

Noble gases

Xenon reacts with fluorine at $873 \ K$ and $7 \ bar$ to form $XeF_4$. In this reaction, the ratio of xenon and fluorine required is

MediumTS EAMCET 2016

View Solution

Which one of the following reactions of xenon compounds is not feasible?

DifficultAIEEE 2009

View Solution

In the preparation of compounds of $Xe$,Bartlett had taken $O^{+}_2 Pt F^{-}_6$ as a base compound. This is because

Difficult

View Solution

Match the Xenon compounds in Column-$I$ with their structures in Column-$II$ and assign the correct code.

Column-$I$ Column-$II$

$(a) XeF_{4}$ $(i) \text{Pyramidal}$

$(b) XeF_{6}$ $(ii) \text{Square planar}$

$(c) XeOF_{4}$ $(iii) \text{Distorted octahedral}$

$(d) XeO_{3}$ $(iv) \text{Square pyramidal}$

Code: $(a) \quad (b) \quad (c) \quad (d)$

Column-$I$	Column-$II$
$(a) XeF_{4}$	$(i) \text{Pyramidal}$
$(b) XeF_{6}$	$(ii) \text{Square planar}$
$(c) XeOF_{4}$	$(iii) \text{Distorted octahedral}$
$(d) XeO_{3}$	$(iv) \text{Square pyramidal}$