The normality of 4% (w/V) NaOH is | vedclass

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(B) Normality $(N)$ is defined as the number of gram equivalents of solute per liter of solution.$4\% \ (w/V)$ $NaOH$ means $4 \ g$ of $NaOH$ is prese

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(B) Normality $(N)$ is defined as the number of gram equivalents of solute per liter of solution.$4\% \ (w/V)$ $NaOH$ means $4 \ g$ of $NaOH$ is present in $100 \ mL$ of solution.Equivalent mass of $NaOH = \frac{	ext{Molar mass}}{	ext{n-factor}} = \frac{40}{1} = 40 \ g/eq$.Number of equivalents $= \frac{	ext{Mass}}{	ext{Equivalent mass}} = \frac{4}{40} = 0.1 \ eq$.Volume of solution $= 100 \ mL = 0.1 \ L$.$N = \frac{	ext{Number of equivalents}}{	ext{Volume in Liters}} = \frac{0.1}{0.1} = 1.0 \ N$.

The normality of $4\% \ (w/V)$ $NaOH$ is

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