The nuclei { }_{6} C^{13} and { }_{7} N^{14} | vedclass

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(D) To determine the relationship between the nuclei ${ }_{6} C^{13}$ and ${ }_{7} N^{14}$,we calculate the number of neutrons $(N)$ in each.For ${ }_

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isotones

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(D) To determine the relationship between the nuclei ${ }_{6} C^{13}$ and ${ }_{7} N^{14}$,we calculate the number of neutrons $(N)$ in each.For ${ }_{6} C^{13}$,the atomic number $Z = 6$ and the mass number $A = 13$. The number of neutrons is $N = A - Z = 13 - 6 = 7$.For ${ }_{7} N^{14}$,the atomic number $Z = 7$ and the mass number $A = 14$. The number of neutrons is $N = A - Z = 14 - 7 = 7$.Since both nuclei have the same number of neutrons $(N = 7)$,they are called isotones.

The nuclei ${ }_{6} C^{13}$ and ${ }_{7} N^{14}$ can be described as

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