The nucleus { }_{Z}^{A} X undergoes the serie | vedclass

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(B) The initial nucleus is ${ }_{Z}^{A} X$.After the first $\alpha$-decay, the nucleus $P$ is formed: ${ }_{Z-2}^{A-4} P$.After the $\beta$-decay of $

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$A-Z-5$

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(B) The initial nucleus is ${ }_{Z}^{A} X$.After the first $\alpha$-decay, the nucleus $P$ is formed: ${ }_{Z-2}^{A-4} P$.After the $\beta$-decay of $P$, the nucleus $Q$ is formed: ${ }_{Z-2+1}^{A-4} Q = { }_{Z-1}^{A-4} Q$.After the second $\alpha$-decay of $Q$, the nucleus $R$ is formed: ${ }_{Z-1-2}^{A-4-4} R = { }_{Z-3}^{A-8} R$.The number of neutrons $N$ in a nucleus ${ }_{Z'}^{A'} R$ is given by $N = A' - Z'$.For nucleus $R$, $A' = A-8$ and $Z' = Z-3$.Therefore, $N = (A-8) - (Z-3) = A - 8 - Z + 3 = A - Z - 5$.

The nucleus ${ }_{Z}^{A} X$ undergoes the series of reactions given below:
${ }_{Z}^{A} X \stackrel{\alpha \text {-decay }}{\longrightarrow} P \stackrel{\beta \text {-decay }}{\longrightarrow} Q \stackrel{\alpha \text {-decay }}{\longrightarrow} R$
The number of neutrons in the nucleus $R$ is

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The nucleus ${ }_{Z}^{A} X$ undergoes the series of reactions given below:${ }_{Z}^{A} X \stackrel{\alpha \text {-decay }}{\longrightarrow} P \stackrel{\beta \text {-decay }}{\longrightarrow} Q \stackrel{\alpha \text {-decay }}{\longrightarrow} R$The number of neutrons in the nucleus $R$ is