The number of all types of isomers of chlorob | vedclass

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(D) The molecular formula of chlorobutane is $C_4H_9Cl$. To find the total number of isomers,we consider both structural and stereoisomers: $1$. $1$-c

Vedclass · Accepted Answer

$5$

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(D) The molecular formula of chlorobutane is $C_4H_9Cl$. To find the total number of isomers,we consider both structural and stereoisomers: $1$. $1$-chlorobutane $(CH_3CH_2CH_2CH_2Cl)$ $2$. $2$-chlorobutane $(CH_3CH_2CHClCH_3)$. This molecule has a chiral center (marked with *),so it exists as a pair of enantiomers ($R$ and $S$ forms). $3$. $1$-chloro-$2$-methylpropane $(CH_3CH(CH_3)CH_2Cl)$ $4$. $2$-chloro-$2$-methylpropane $(CH_3C(Cl)(CH_3)CH_3)$ Counting these: $1$-chlorobutane $(1)$,$2$-chlorobutane ($2$ enantiomers),$1$-chloro-$2$-methylpropane $(1)$,and $2$-chloro-$2$-methylpropane $(1)$. Total = $1 + 2 + 1 + 1 = 5$.

The number of all types of isomers of chlorobutane $(C_4H_9Cl)$ is:

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