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Question

(C) In anaerobic respiration (fermentation),one molecule of glucose undergoes glycolysis to produce a net gain of $2$ $ATP$ molecules.To produce $38$

Vedclass · Accepted Answer

$19$

Vedclass · Answer

(C) In anaerobic respiration (fermentation),one molecule of glucose undergoes glycolysis to produce a net gain of $2$ $ATP$ molecules.To produce $38$ $ATP$ molecules under anaerobic conditions,the number of glucose molecules required is calculated as:$	ext{Number of glucose molecules} = \frac{	ext{Total ATP required}}{	ext{ATP produced per glucose}} = \frac{38}{2} = 19$.Therefore,$19$ glucose molecules are required.

The number of glucose molecules required to produce $38$ $ATP$ molecules under anaerobic conditions by a yeast cell is

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