The number of ions per mole of a complex [CoC | vedclass

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(C) The complex $[Co(NH_3)_5Cl]Cl_2$ ionizes in an aqueous solution as follows:$[Co(NH_3)_5Cl]Cl_2(aq) \rightarrow [Co(NH_3)_5Cl]^{2+}(aq) + 2Cl^{-}(a

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$3$

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(C) The complex $[Co(NH_3)_5Cl]Cl_2$ ionizes in an aqueous solution as follows:$[Co(NH_3)_5Cl]Cl_2(aq) \rightarrow [Co(NH_3)_5Cl]^{2+}(aq) + 2Cl^{-}(aq)$From the dissociation,we get $1$ complex cation $[Co(NH_3)_5Cl]^{2+}$ and $2$ chloride anions $Cl^{-}$.Therefore,the total number of ions produced per mole of the complex is $1 + 2 = 3$ ions.

The number of ions per mole of a complex $[CoCl_2 \cdot 5NH_3]Cl_2$ in aqueous solution will be

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