The number of isoelectronic species among Sc^ | vedclass

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(B) SpeciesElectrons$Sc^{3+}$$18$$Cr^{2+}$$22$$Mn^{3+}$$22$$Co^{3+}$$24$$Fe^{3+}$$23$The isoelectronic species are $Cr^{2+}$ and $Mn^{3+}$, so $n = 2$

Vedclass · Accepted Answer

$6$

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(B) SpeciesElectrons$Sc^{3+}$$18$$Cr^{2+}$$22$$Mn^{3+}$$22$$Co^{3+}$$24$$Fe^{3+}$$23$The isoelectronic species are $Cr^{2+}$ and $Mn^{3+}$, so $n = 2$.The complex $CoCl_{3}(en)_{2}NH_{3}$ reacts with excess $AgNO_{3}$ to form $2$ moles of $AgCl$, indicating the formula is $[Co(en)_{2}NH_{3}Cl]Cl_{2}$.In this complex, $Co$ is in the $+3$ oxidation state ($3d^{6}$ configuration).For an octahedral complex with a strong field ligand like $en$, the $6$ electrons occupy the $t_{2g}$ orbitals as $t_{2g}^{6} e_{g}^{0}$.Therefore, the number of electrons in the $t_{2g}$ orbital is $6$.

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