The number of isomers possible for the octahedral complex $[CoCl_{2}(en)(NH_{3})_{2}]^{+}$ is,

  • A
    Two
  • B
    Three
  • C
    No isomer
  • D
    Four isomers

Explore More

Similar Questions

The number of possible optical isomers for the complexes $MA_{2}B_{2}$ with $sp^{3}$ and $dsp^{2}$ hybridised metal atom,respectively,is.
Note : $A$ and $B$ are unidentate neutral and unidentate monoanionic ligands,respectively.

The two compounds pentaamminesulphatocobalt $(III)$ bromide and pentaamminesulphatocobalt $(III)$ chloride represent:

Among $(i)$ $[Cr(en)_{3}]^{3+}$,$(ii)$ $trans-[Cr(en)_{2}Cl_{2}]^{+}$,$(iii)$ $cis-[Cr(en)_{2}Cl_{2}]^{+}$,$(iv)$ $[Co(NH_{3})_{4}Cl_{2}]^{+}$,the optically active complexes are:

Which of the following complexes exhibits the highest paramagnetic behaviour? (where $gly = \text{glycine}$,$en = \text{ethylenediamine}$,and $bpy = \text{bipyridyl}$ moieties. At. nos. $Ti = 22, V = 23, Fe = 26, Co = 27$)

How many optical isomers are possible for the complex $[Pt(NH_3)_2(CN)_2]$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo