The number of molecules in 8.96 L of a gas a | vedclass

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(D) At $STP$ ($0^{\circ}C$ and $1 \ atm$),$22.4 \ L$ of any gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number).Number of moles in $8.96

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$24.08 	imes 10^{22}$

Vedclass · Answer

(D) At $STP$ ($0^{\circ}C$ and $1 \ atm$),$22.4 \ L$ of any gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number).Number of moles in $8.96 \ L = \frac{8.96 \ L}{22.4 \ L/mol} = 0.4 \ mol$.Number of molecules $= 	ext{moles} 	imes N_A = 0.4 	imes 6.022 	imes 10^{23}$.$= 2.4088 	imes 10^{23} = 24.088 	imes 10^{22} \approx 24.08 	imes 10^{22}$.

The number of molecules in $8.96 \ L$ of a gas at $0^{\circ}C$ and $1 \ atm$ pressure is approximately

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