The number of molecules in 4.25 , g of ammoni | vedclass

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Question

(B) The molecular weight of $NH_3$ is $17 \, g/mol$.According to the mole concept,$17 \, g$ of $NH_3$ contains $6.022 	imes 10^{23}$ molecules.Theref

Vedclass · Accepted Answer

$1.5 	imes 10^{23}$

Vedclass · Answer

(B) The molecular weight of $NH_3$ is $17 \, g/mol$.According to the mole concept,$17 \, g$ of $NH_3$ contains $6.022 	imes 10^{23}$ molecules.Therefore,the number of moles in $4.25 \, g$ of $NH_3$ is $\frac{4.25 \, g}{17 \, g/mol} = 0.25 \, mol$.The number of molecules $= 	ext{moles} 	imes N_A = 0.25 	imes 6.022 	imes 10^{23} \approx 1.505 	imes 10^{23}$ molecules.Thus,the correct option is $(B)$.

The number of molecules in $4.25 \, g$ of ammonia is:

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