The number of molecules in 16 g of methane i | vedclass

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Question

(B) The molar mass of methane $(CH_4)$ is $12 + (4 	imes 1) = 16 \ g/mol$. Given mass of $CH_4 = 16 \ g$. Number of moles = $\frac{	ext{Given mass}}

Vedclass · Accepted Answer

$6.02 	imes 10^{23}$

Vedclass · Answer

(B) The molar mass of methane $(CH_4)$ is $12 + (4 	imes 1) = 16 \ g/mol$. Given mass of $CH_4 = 16 \ g$. Number of moles = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{16 \ g}{16 \ g/mol} = 1 \ mol$. Number of molecules = $	ext{Number of moles} 	imes N_A = 1 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{23}$ molecules. Thus,the correct option is $(B)$.

The number of molecules in $16 \ g$ of methane is

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