The number of non-ionisable protons present in the product $B$ obtained from the following reaction is:
$3C_{2}H_{5}OH + PCl_{3} \rightarrow 3C_{2}H_{5}Cl + H_{3}PO_{3} (A)$
$H_{3}PO_{3} + PCl_{3} \rightarrow H_{4}P_{2}O_{5} (B) + HCl$

  • A
    $9$
  • B
    $2$
  • C
    $4$
  • D
    $3$

Explore More

Similar Questions

Among the given group $14$ elements,the one with highest density is

Anhydrous mercurous chloride can be prepared by

$(1)$ Half-life of $^{14}C$ is $...........$
$(2)$ $..........$ isotope of carbon is used in radiocarbon dating.
$(3)$ Main component of ceramic,cement and glass is $........$

Match the following:
List-$I$ (Compound)List-$II$ (Use)
$A$. Kieselghur$I$. Chromatographic material
$B$. Silica gel$II$. Softening of hard water
$C$. $ZSM-5$$III$. Filtration plants
$D$. Hydrated zeolites$IV$. To convert alcohol directly into gasoline

Mark the oxide which is amphoteric in character.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo