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(C) The given compound is $CH_3-CH=CH-CH(CH_3)-CH=CH-CH(CH_3)-CH=CH-CH_3$. Upon complete ozonolysis $(O_3/Zn, H_2O)$,the double bonds are cleaved. The

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$2$

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(C) The given compound is $CH_3-CH=CH-CH(CH_3)-CH=CH-CH(CH_3)-CH=CH-CH_3$. Upon complete ozonolysis $(O_3/Zn, H_2O)$,the double bonds are cleaved. The products formed are: $1$. $CH_3CHO$ (Acetaldehyde) - Optically inactive. $2$. $OHC-CH(CH_3)-CHO$ (Methylmalonaldehyde) - This molecule has a chiral center at the carbon atom attached to the methyl group. Since the ozonolysis of the given compound produces two molecules of $CH_3CHO$ and two molecules of $OHC-CH(CH_3)-CHO$,we evaluate the optical activity of $OHC-CH(CH_3)-CHO$. The structure $OHC-CH(CH_3)-CHO$ contains a chiral center,making it optically active. Thus,the products that are optically active are the two molecules of $OHC-CH(CH_3)-CHO$. Therefore,the total number of optically active products is $2$.

The number of optically active products obtained from the complete ozonolysis of the given compound is:

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