The number of possible enantiomeric pair(s) p | vedclass

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(A) Bromination of compound $I$ ($2,3$-dimethylbut-$2$-ene) with $Br_2$ yields $2,3$-dibromo-$2,3$-dimethylbutane. This product is a $meso$ compound d

Vedclass · Accepted Answer

$0, 1$

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(A) Bromination of compound $I$ ($2,3$-dimethylbut-$2$-ene) with $Br_2$ yields $2,3$-dibromo-$2,3$-dimethylbutane. This product is a $meso$ compound due to the presence of a plane of symmetry. Therefore,it does not form any enantiomeric pair.Bromination of compound $II$ ($2$-methylbut-$1$-ene) with $Br_2$ (followed by addition) yields $1,2$-dibromo-$2$-methylbutane. The carbon atom at position $2$ becomes a chiral center $(C^*)$. This chiral compound exists as a pair of enantiomers ($d$ and $l$ forms),which are non-superimposable mirror images of each other. Thus,it produces $1$ enantiomeric pair.Therefore,the number of enantiomeric pairs produced from $I$ and $II$ are $0$ and $1,$ respectively. The correct option is $(a).$

The number of possible enantiomeric pair$(s)$ produced from the bromination of $I$ and $II,$ respectively,are

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