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(D) $1$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $[Ar] 3d^6$. $NH_3$ is a Strong Field Ligand $(SFL)$,causing pairing. Hybridization is $d^2 sp^3$.$2$. $SF_

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(D) $1$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $[Ar] 3d^6$. $NH_3$ is a Strong Field Ligand $(SFL)$,causing pairing. Hybridization is $d^2 sp^3$.$2$. $SF_6$: Sulphur has $6$ valence electrons and forms $6$ bonds. Hybridization is $sp^3 d^2$.$3$. $[CrF_6]^{3-}$: $Cr^{3+}$ is $[Ar] 3d^3$. Hybridization is $d^2 sp^3$.$4$. $[CoF_6]^{3-}$: $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a Weak Field Ligand $(WFL)$,no pairing. Hybridization is $sp^3 d^2$.$5$. $[Mn(CN)_6]^{3-}$: $Mn^{3+}$ is $[Ar] 3d^4$. $CN^-$ is $SFL$. Hybridization is $d^2 sp^3$.$6$. $[MnCl_6]^{3-}$: $Mn^{3+}$ is $[Ar] 3d^4$. $Cl^-$ is $WFL$. Hybridization is $sp^3 d^2$.Species with $sp^3 d^2$ hybridization are $SF_6, [CoF_6]^{3-}$,and $[MnCl_6]^{3-}$.Total count is $3$.

The number of species from the following that are involved in $sp^3 d^2$ hybridization is $[Co(NH_3)_6]^{3+}, SF_6, [CrF_6]^{3-}, [CoF_6]^{3-}, [Mn(CN)_6]^{3-}$ and $[MnCl_6]^{3-}$.

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