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(B) To find the number of structural isomers for $C_4H_8F_2$,we consider the carbon skeletons of butane $(C_4H_{10})$ and isobutane $(CH_3CH(CH_3)CH_3

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(B) To find the number of structural isomers for $C_4H_8F_2$,we consider the carbon skeletons of butane $(C_4H_{10})$ and isobutane $(CH_3CH(CH_3)CH_3)$: $1$. For the $n$-butane skeleton $(CH_3-CH_2-CH_2-CH_3)$: - $1,1$-difluorobutane - $1,2$-difluorobutane - $1,3$-difluorobutane - $1,4$-difluorobutane - $2,2$-difluorobutane - $2,3$-difluorobutane $2$. For the isobutane skeleton $(CH_3-CH(CH_3)-CH_3)$: - $1,1$-difluoro-$2$-methylpropane - $1,2$-difluoro-$2$-methylpropane - $1,3$-difluoro-$2$-methylpropane Counting these gives a total of $6 + 3 = 9$ structural isomers. Therefore,the correct option is $B$.

The number of structural isomers possible for the molecular formula $C_4H_8F_2$ are

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