The number of turns in the coil of an AC gene | vedclass

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(B) The induced electromotive force $(\varepsilon)$ in a rotating coil is given by the formula: $\varepsilon = N B A \omega \sin(\omega t)$.For the ma

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$4.5$

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(B) The induced electromotive force $(\varepsilon)$ in a rotating coil is given by the formula: $\varepsilon = N B A \omega \sin(\omega t)$.For the maximum induced emf $(\varepsilon_{\max})$, we set $\sin(\omega t) = 1$.Thus, the formula becomes: $\varepsilon_{\max} = N B A \omega$.Given values:Number of turns $(N)$ = $100$Magnetic field strength $(B)$ = $0.3 \ T$Area $(A)$ = $2.5 \ m^2$Angular velocity $(\omega)$ = $60 \ rad \ s^{-1}$Substituting these values into the formula:$\varepsilon_{\max} = 100 	imes 0.3 	imes 2.5 	imes 60$$\varepsilon_{\max} = 30 	imes 2.5 	imes 60$$\varepsilon_{\max} = 75 	imes 60 = 4500 \ V$.Converting to $kV$:$\varepsilon_{\max} = 4.5 \ kV$.

The number of turns in the coil of an $AC$ generator is $100$ and its cross-sectional area is $2.5 \ m^2$. The coil is revolving in a uniform magnetic field of strength $0.3 \ T$ with a uniform angular velocity of $60 \ rad \ s^{-1}$. The value of maximum induced emf is . . . . . . $kV$.

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