The number of turns of primary and secondary | vedclass

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(C) The mutual inductance $M$ of a transformer is given by the formula $M = \frac{\mu_0 N_1 N_2 A}{l}$,where $N_1$ and $N_2$ are the number of turns i

Vedclass · Accepted Answer

$25$

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(C) The mutual inductance $M$ of a transformer is given by the formula $M = \frac{\mu_0 N_1 N_2 A}{l}$,where $N_1$ and $N_2$ are the number of turns in the primary and secondary coils,$A$ is the cross-sectional area,and $l$ is the length of the core.From the formula,we see that $M \propto N_1 N_2$.Initially,$N_1 = 5$ and $N_2 = 10$,so $N_1 N_2 = 5 	imes 10 = 50$.Given $M_1 = 25\,H$.Now,the new number of turns are $N_1' = 10$ and $N_2' = 5$,so $N_1' N_2' = 10 	imes 5 = 50$.Since the product of the number of turns remains the same $(N_1 N_2 = N_1' N_2')$,the mutual inductance remains unchanged.Therefore,$M_2 = M_1 = 25\,H$.

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