The number of unpaired electrons in Cr^{3+} i | vedclass

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Question

(A) The atomic number of Chromium $(Cr)$ is $24$.The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.To form $Cr^{3+}$,we remove $3$ electrons: o

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$3$

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(A) The atomic number of Chromium $(Cr)$ is $24$.The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.To form $Cr^{3+}$,we remove $3$ electrons: one from the $4s$ orbital and two from the $3d$ orbital.The electronic configuration of $Cr^{3+}$ becomes $[Ar] 3d^3$.In the $3d^3$ configuration,there are $3$ unpaired electrons in the $d$-orbitals.Therefore,the correct option is $A$.

The number of unpaired electrons in $Cr^{3+}$ ion is

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