The number of unpaired electrons in Mn^{2+} i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The atomic number of $Mn$ is $25$.The electronic configuration of $Mn$ is $[Ar] 3d^5 4s^2$.When $Mn$ forms $Mn^{2+}$ ion, it loses two electrons f

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The atomic number of $Mn$ is $25$.The electronic configuration of $Mn$ is $[Ar] 3d^5 4s^2$.When $Mn$ forms $Mn^{2+}$ ion, it loses two electrons from the $4s$ orbital.Thus, the electronic configuration of $Mn^{2+}$ is $[Ar] 3d^5$.In the $3d$ subshell, there are $5$ orbitals, and according to Hund's rule, each orbital will be occupied by one electron.Therefore, there are $5$ unpaired electrons in $Mn^{2+}$ ion.

The number of unpaired electrons in $Mn^{2+}$ ion is

Similar Questions

Which of the following statements are correct? $(1)$ Manganese can exhibit a $+7$ oxidation state. $(2)$ Zinc forms colored ions. $(3)$ $[CoF_6]^{3-}$ is diamagnetic. $(4)$ $Sc$ can exhibit a $+4$ oxidation state. $(5)$ $Zn$ exhibits only a $+2$ oxidation state.

In the $3d$ series of transition elements,the atomic radius of $Zn$ increases instead of decreasing because...

The calculated magnetic moment (in Bohr magnetons) of $Cu^{2+}$ ion is:

Among the following metals,the most dense is

The magnetic moment of $2.84 \, B.M.$ is exhibited by which of the following ions? (Atomic numbers: $Ni = 28, Ti = 22, Cr = 24, Co = 27$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module